Grouped Frequency Tables

This lesson covers: 

  1. Grouped frequency tables
  2. Calculating mid-interval values for grouped data
  3. Estimating the mean, mode and range from a grouped frequency table

Introduction to grouped frequency tables


Grouped frequency tables categorise data into intervals, or classes, to simplify large data sets.

Each category, known as a class, has a specified range instead of an exact data point.

Height (mm)FrequencyMid-interval value
5 < h\leq10127.5
10 < h \leq151512.5


No overlapping between classes

To ensure each data value fits into a unique class, we use inequalities. 

The first class in the table above contains values which are larger than 5 up to and including 10.

For example, a value of 10.0 falls in the first class, whereas 10.1 would fit into the second.


Determining mid-interval value 

To find this, sum the boundaries of a class and halve the result.

For example, for heights of 5 to 10 mm, the mid-interval value is 25+10 = 7.5.

Identifying the modal class from a grouped frequency table


The modal class is the class which occurs most frequently. 

The table below shows the heights of students in a tutor group.

height (cm)frequency
100 < h \leq 1104
110 < h \leq 1208
120 < h \leq 1306
130 < h \leq 1403
140 < h \leq 1502

The most frequently occurring class is 110 < h  120 with a frequency of 8. 

Identifying the median from a grouped frequency table


height (cm)frequency
100 < h \leq 1104
110 < h \leq 1208
120 < h \leq 1306
130 < h \leq 1403
140 < h \leq 1502

The median class contains the  2n + 1 value. 


Where:

  • n = total frequency


For the example above:

Total frequency = 4 + 8 + 6+ 3 + 2 = 23


Location of the median class = 223 + 1 = 12


The 12th value lies within the 110 < h  120 class, making this the median class.

Identifying the range from a grouped frequency table


height (cm)frequency
100 < h \leq 1104
110 < h \leq 1208
120 < h \leq 1306
130 < h \leq 1403
140 < h \leq 1502

The range can be identified by subtracting the minimum value from the lowest class from the maximum value from the highest class.


In the example above the range = 150 - 100 = 50 cm

Estimating mean from group data


To calculate the mean from a grouped frequency table:

  1. Insert a third column for mid-interval value.
  2. Add a fourth column titled frequency x mid-interval value.
  3. Calculate the total frequency and total (frequency x mid-interval value).
  4. Mean = total frequencytotal (frequency x mid−interval value)


Example:

Mass (kg)FrequencyMid-interval value (kg)Frequency x mid-interval value
40 < w \leq 50845360
50 < w \leq 601655880
60 < w \leq 701265780
70 < w \leq 80675450
Total = 42Total = 2,470


Mean weight = total frequencytotal (frequency x mid−interval value)=422,470 = 58.8 kg

Worked Example 1: Identifying the mean from a grouped frequency table 


Calculate the mean from the grouped frequency table below.

Time taken (minutes)Frequency
0 < m \leq103
10 < m \leq208
20 < m \leq3011
30 < m \leq409
40 < m \leq509
  1. Insert a third column for mid-interval value. 
  2. Add a fourth column for frequency x mid-interval value.
  3. Calculate the total (frequency x mid-interval value).
  4. Mean = total frequencytotal (frequency x mid interval value)
Time taken (minutes)FrequencyMid-interval valueFrequency x mid-interval value
0 < m \leq103515
10 < m \leq20815120
20 < m \leq301125275
30 < m \leq40935315
40 < m \leq50945405
Total = 40Total = 1,130


mean = 401,130 = 28.25 minutes

Which is the modal class?

age (years)frequency
0 < a \leq 54
5 < a \leq 107
10 < a \leq 153
15 < a \leq 205

10 < a  15

0 < a  5

5 < a  10

15 < a  20

0

/

1

Which class contains the median value?

age (years)frequency
0 < a \leq 54
5 < a \leq 107
10 < a \leq 153
15 < a \leq 205

10 < a  15

0 < a  5

5 < a  10

15 < a  20

0

/

1

Which is the modal class?

Height (cm)frequency
140 < h \leq 1507
150 < h \leq 16010
160 < h \leq 17015
170 < h \leq 1808

140 < h  150

170 < h  180

160 < h  170

150 < h  160

0

/

1