Redox Reactions Involving Transition Metal Ions

This lesson covers: 

  1. How transition metals can exist in various oxidation states
  2. Using redox potentials to determine the ease of reduction
  3. Redox reactions of transition metals

Transition metals have variable oxidation states

Transition metals can exist in various positive oxidation states in compounds and complexes. This occurs due to the similar energies of the outer d orbital electrons, allowing multiple oxidation states to be stable.


For example, vanadium exhibits four oxidation states from +2 to +5, each with different coloured ions:

Oxidation stateIon formulaIon colour
+5VO2+Yellow
+4VO2+Blue
+3V3+Green
+2V2+Violet

Redox potentials indicate ease of reduction

The redox potential, E, indicates how easily an ion is reduced. Ions with higher, more positive E values are more easily reduced to lower oxidation states.

Half reactionE (V)
Cr3+/Cr2+-0.41
Cu2+/Cu++0.15

For example, Cu2+ has a higher redox potential than Cr3+ so is more easily reduced.


However, E values are measured under standard conditions, so the actual redox potential can vary depending on:

  • Ligands - E° assumes metal ions are surrounded by water ligands in aqueous solution. Other ligands that form stronger bonds with the metal ion can raise or lower the potential by stabilising a particular oxidation state.
  • pH - Acidic conditions provide excess H+ ions needed for reduction of some metal ions. For example: 

VO2+(aq) + 2H+(aq) + e- ➔ VO2+(aq) + H2O(l)

Alkaline conditions favour oxidation reactions that consume OH- ions instead. For example:

Cr(OH)3(s) + 5OH-(aq) ➔ CrO42-(aq) + 4H2O(l) + 3e-


In general, more acidic solutions give higher, more positive redox potentials.

Interconversion between common transition ions

Transition elements can change oxidation state by gaining or losing electrons in redox reactions.

For complex ions in solution, this change in oxidation state is often accompanied by a distinctive colour change.

You need to know about the redox reactions of iron, chromium, and copper.

Interconversion between Fe2+ and Fe3+

Pale-green Fe2+(aq) ions are oxidised to yellow Fe3+(aq) ions by acidified potassium manganate(VII) solution, KMnO4(aq), in acidic conditions:

MnO4- + 8H+ + 5Fe2+ ➔ Mn2+ + 4H2O + 5Fe3+

  • Iron is oxidised from +2 to +3.
  • Manganese is reduced from +7 to +2.


Fe3+ is reduced back to Fe2+ by iodide ions (I-)(aq):

2I- + 2Fe3+ ➔ 2Fe2+ + I2

  • Iodine is oxidised from -1 to 0.
  • Iron is reduced from +3 to +2.

Interconversion between Cr3+ and Cr2O72-

Dark-green Cr3+(aq) ions are oxidised to yellow CrO42-(aq) ions by warming with hydrogen peroxide solution, H2O2(aq), in alkaline conditions:

3H2O2 + 2[Cr(OH)6]3- ➔ 2OH- + 2CrO42- + 8H2O

  • Chromium is oxidised from +3 to +6.
  • Oxygen is reduced from -1 to -2.


Orange Cr2O72- ions are formed by adding sulfuric acid:

2CrO42- + 2H+ ➔ Cr2O72- + H2O


Cr2O72- is reduced back to Cr3+ by zinc in acidic conditions:

Cr2O72- + 14H+ + 3Zn ➔ 2Cr3+ + 7H2O + 3Zn2+

  • Zinc is oxidised from 0 to +2.
  • Chromium is reduced from +6 to +3.

Reduction of Cu2+ and disproportionation of Cu+

Pale blue Cu2+(aq) ions are reduced to the white precipitate copper(I) iodide, CuI, by iodide ions (I-).


The dissolved iodine turns the solution brown:

2Cu2+(aq) + 4I-(aq) ➔ 2CuI(s) + I2(aq)

  • Iodide is oxidised from -1 to 0.
  • Copper is reduced from +2 to +1.


The colourless Cu+ ion is unstable in aqueous solution and readily disproportionates into Cu2+(aq) and Cu(s):

2Cu+(aq) ➔ Cu2+(aq) + Cu(s)

  • Cu+ is both oxidised (from +1 to +2) and reduced (from +1 to 0).