Question 1
Propanone has a much higher boiling temperature than butane.
The main reason for this is
propanone has permanent dipole-dipole forces between its molecules while butane does not
propanone forms hydrogen bonds between its molecules while butane does not
propanone has stronger induced dipole-dipole forces between its molecules than butane
the carbon-oxygen double bond in propanone is very strong
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Question 2
CH3CH2COCH2CH3 reacts with hydrogen cyanide to form an organic product called a cyanohydrin.
Which feature applies to the cyanohydrin product?
it has one chiral centre
it is formed by electrophilic addition
it is formed via an intermediate which contains the C-OH group
its formation requires the use of cyanide ions as a catalyst
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Question 3
Structural isomerism and stereoisomerism should be considered when answering this question.
Each of the following carbonyl compounds is reacted with NaBH4. The product of each reaction is heated with concentrated phosphoric acid at 170°C, generating one product or a mixture of isomers.
Which carbonyl compound will produce the most isomers?
butanal
butanone
pentan-3-one
propanone
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Question 4
Ketones react with hydrogen cyanide, HCN, in the presence of cyanide ions, CN-.
Which of these ketones does not form a racemic mixture in this reaction?
CH3CH2CH2COCH3
CH3CH2COCH2CH3
CH3CH2CH2CH2COCH3
CH3CH2CH2COCH2CH3
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Question 5
Ketones react with hydrogen cyanide, HCN, in the presence of cyanide ions, CN-.
This type of reaction is classified as
nucleophilic substitution
nucleophilic addition
electrophilic addition
electrophilic substitution
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Question 6
Name the functional group in HCHO.
aldehyde
ketone
alcohol
carboxylic acid
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Question 7
What is the functional group in C6H5COCH3?
aldehyde
carboxylic acid
ester
ketone
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Question 8
Which of the following compounds would form an orange-red precipitate when heated with Fehling’s solution?
CH3CH2CN
CH3CH2COOH
CH3CHO
CH3COCH3
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Question 9
Which alcohol could not be produced by the reduction of an aldehyde or a ketone?
2,2-dimethylpropan-1-ol
2-methylbutan-2-ol
3-methylbutan-2-ol
pentan-3-ol
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Question 10
Which compound forms optically active compounds on reduction?
CH3CH2C(CH3)=CHCH3
CH3CH2C(CH3)=CH2
CH3COCH3
CH3CH2COCH3
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